2y^2-36y=0

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Solution for 2y^2-36y=0 equation: 



2y^2-36y=0

a = 2; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·2·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*2}=\frac{0}{4}
=0
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*2}=\frac{72}{4}
=18
$

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